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col.c파일을 열어보면,
#include <stdio.h>
#include <string.h>
unsigned long hashcode = 0x21DD09EC;
unsigned long check_password(const char* p){
int* ip = (int*)p;
int i;
int res=0;
for(i=0; i<5; i++){
res += ip[i];
}
return res;
}
int main(int argc, char* argv[]){
if(argc<2){
printf("usage : %s [passcode]\n", argv[0]);
return 0;
}
if(strlen(argv[1]) != 20){
printf("passcode length should be 20 bytes\n");
return 0;
}
if(hashcode == check_password( argv[1] )){
system("/bin/cat flag");
return 0;
}
else
printf("wrong passcode.\n");
return 0;
}
그냥 글자수 끼워맞추기 문제인것같다.
21DD09EC >> 6C5CEC8*5
>>6C5CEC8*4 + 6C5CECC
페이로드 >
./col `python -c 'print "\xc8\xce\xc5\x06"*4+"\xcc\xce\xc5\x06"'`
daddy! I just managed to create a hash collision :)
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